I got to like A(B+C)/C=B but I can't get any farther!!!
I need help solving for "B" from A=BC/B+C.?
I will assume the equation is
A = BC/(B + C)
=%26gt; A(B + C) = BC
=%26gt; AB + AC = BC
=%26gt; BC - AB = AC
=%26gt; B(C - A) = AC
=%26gt; B = AC/(C - A)
Reply:multiply both sides by B+C
then you have
a(b+c)=bc
then move bc to the same side and distribute the a
ab+ac-bc=0 now move ac to one side
ab-bc=-ac now you factor out a b from the left side
b(a-c)=-ac then divide by a-c both sides and your finished
b= -ac/a-c
Reply:Muliply B+C with A...
BA+CA=BC
Get all the Bs on one side...
BA-BC=-CA
Factor out the B...
B(A-C)=-CA
Divide to free up B by itself...
B=(-CA)/((A-C)
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