154 grams of antifreeze absorbs 5045 joules of energy in going from 21.0°C to 350°C.what is the specific heat

of the antifreeze?





a. 4.18J/g°C


b. 0.936J/g°C


c. 2.34J/g°C


d. 1.56J/g°C

154 grams of antifreeze absorbs 5045 joules of energy in going from 21.0°C to 350°C.what is the specific heat
use the formula





E = c*m*(change in temperature)





so your E is your joules


your m is your mass (154)


and your change in temperature is (350-21)





then solve for "c" and that will be your specific heat!
Reply:I'm assuming you mean 35.0 C, not 350, otherwise none of the answers is correct.





heat = specific heat * mass * temperature change


specific heat = 5045/(154*14) = 2.34 J/g C