If a,b,c are rootrs of third order equation find a(ab)+b(bc)+c(ca) ,and aaa+bbb+ccc?

if xpower3+pxpower2+qx+r is the third order equation find the sum of (a square multiply by b+b square multiply by c+c square multiply by a) and the sum of (cube of a+cube of b+ cube of c)

If a,b,c are rootrs of third order equation find a(ab)+b(bc)+c(ca) ,and aaa+bbb+ccc?
Do your own homework, how do you expect to pass any tests if you don't do the work beforehand
Reply:I'm not sure if this is what you're after, but consider this:


a,b,c are the roots of the equation. That means putting in a, b, or c as x with make the equation = 0. So





a^3 + p*a^2 + q*a + r = 0


b^3 + p*b^2 + q*a + r = 0


c^3 + p*c^2 + q*c + r = 0





You can use each equation to find the values of each root, each root squared and each root cubed.





For example:





a^3 = -p*a^2 - q*a - r


b^3 = -p*b^2 - q*b - r


c^3 = -p*c^2 - q*c - r





then a^3 + b^3 + c^3 = -p*a^2 - q*a - r - p*b^2 - q*b - r - p*c^2 - q*c - r





You can do the same for a^2, a ,b^2, b, c^2 and c.
Reply:yes.
Reply:whhhhhhhhhhaaaaaaaaaaaaaaa umm it's 3
Reply:I don't know the answer, but you can start by multiplying out


(x-a)(x-b)(x-c).
Reply:Oh yeah this is easy! The answer is asfrjkvg
Reply:Answer: Johnny will have 3 apples and billy will have a sore wrist