a+b=c
c-b=a
what does
bc (b times c) equal?
If a+b=c, and c-b=a, what does bc = ?
if
a + b = c
then
b = c - a
and
c = a + b
so
bc = (c-a)(a+b)
*********************************
Unfortunately, as many other answers tried to do,
it cannot be simplified past this because C is dependent on both the a and b values
To the people who said that bc = b squared OR c squared,
that is obviously wrong.
proved wrong::
Let a=2, b=10
a + b = c
c=12
bc= 10 x 12 = 120
b squared is 100
c squared is 144
those are INCORRECT.
using my formula,
bc = (c-a)(a+b)
bc = (12-2)(2+10)
bc = 10 x 12
bc = 120
I hope I made sense!!
Reply:bc = b*(a+b)
= ab + b squared
or = b squared (a/b +1)
Reply:wait.... what? is there some kind of property to that?!
Reply:i don't know if that's even possible...have you considered "NO Solution"?
Reply:a + b = c
a = c - b {subtract b from both sides}
This is the same as your second piece of information
Impossible
Reply:bc==c^2-2ac+2a^2-c
given a+b=c
c-b=a
then (a+b)(c-b)=ac this is true, by MPE)
solution...
(a+b)(c-b)= ac
ac-ab+bc-b^2=ac
bc= b^2 +ab
from the first equation we can derive b=c-a
then we substitute
bc=(c-a)^2 - (c-a)(a)
=c^2-2ac+a^2 - c + a^2
=c^2-2ac+2a^2-c
Reply:i know that
a/b divided by c/d = ac/bd
/=fractions
Reply:a+b=c
c-b=a
just using the first equation we can solve this;
a+b=c ... therefore b = c -a
therefore B * C = (a+b)(c-a) = ac +bc -a² -ab
EASY ANS: (a+b)*(c-a) OR -a² -ab +bc +ac
This is interesting because we are saying that:
bc = -a² -ab +bc +ac ... %26lt;-- both side have a bc
which means
0 = -a² -ab +ac
0 = -a(a -b +c) = -a(a +c -b) = -a(a +a) %26lt;-- c-b=a is a given
=%26gt; 0 = -a(2a) = -2a² .
=%26gt; a = 0
which means that:
a+b=c ... is really saying ... 0 +b = c
c-b=a ... is really ... c -b = 0
which means b and c are equal!
Therefore the answers to the question is actually:
b*c = b² = c²
CORRECT ANS: bc = b² = c²
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